(((2x-3)^2)/(3x))=-1

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Solution for (((2x-3)^2)/(3x))=-1 equation: 


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

((2*x-3)^2)/(3*x) = -1 // + 1

((2*x-3)^2)/(3*x)+1 = 0

((2*x-3)^2)/(3*x)+(1*3*x)/(3*x) = 0

(2*x-3)^2+1*3*x = 0

4*x^2-9*x+9 = 0

4*x^2-9*x+9 = 0

4*x^2-9*x+9 = 0

DELTA = (-9)^2-(4*4*9)

DELTA = -63

DELTA < 0

1 = 0

1/(3*x) = 0

1/(3*x) = 0 // * 3*x

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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